The branch of mathematics dealing with symbols and the rules for manipulating those symbols. Algebra is the foundation for all higher mathematics.
Algebra is one of the broadest and most fundamental branches of mathematics. At its core, algebra is about finding unknown values by using letters (called variables) to represent numbers in equations and formulas. The word "algebra" comes from the Arabic word al-jabr, meaning "reunion of broken parts," from the title of a 9th-century book by mathematician al-Khwarizmi.
Algebra provides the language and tools that are essential to nearly every area of mathematics, science, engineering, economics, and computer science. When you learn algebra, you're not just learning to solve equations — you're learning to think logically and abstractly.
A variable is a symbol (usually a letter like x, y, or z) that represents an unknown or changeable value. An algebraic expression is a combination of variables, numbers, and operations.
Simplify: 3x + 5y - 2x + 8y
Group like terms: (3x - 2x) + (5y + 8y) = x + 13y
When evaluating expressions, follow this order:
A linear equation is an equation where the highest power of the variable is 1. The graph of a linear equation is always a straight line.
Where a, b, and c are constants, and a ≠ 0.
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 goal is to isolate the variable on one side of the equation using inverse operations:
Step 1: Subtract 7 from both sides: 3x = 15
Step 2: Divide both sides by 3: x = 5
Check: 3(5) + 7 = 15 + 7 = 22 ✓
Where m is the slope (rate of change) and b is the y-intercept (where the line crosses the y-axis).
An inequality compares two expressions using symbols like <, >, ≤, or ≥. Unlike equations, inequalities have a range of solutions.
Solve inequalities the same way as equations, with one critical rule:
Step 1: Subtract 3 from both sides: -2x > 8
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 2: Divide by -2 (flip the sign!): x < -4
The solution is all values of x less than -4.
A compound inequality combines two inequalities joined by "and" or "or":
A polynomial is an expression consisting of variables and coefficients, combined using addition, subtraction, and multiplication, with non-negative integer exponents.
Addition/Subtraction: Combine like terms (same variable and exponent).
Multiplication: Use the distributive property (FOIL for binomials).
Multiply: (x + 3)(x - 5)
First: x · x = x²
Outer: x · (-5) = -5x
Inner: 3 · x = 3x
Last: 3 · (-5) = -15
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: x² - 5x + 3x - 15 = x² - 2x - 15
A quadratic equation has the standard form:
If the quadratic can be written as a product of two binomials, set each factor equal to zero.
x² - 5x + 6 = 0
(x - 2)(x - 3) = 0
x = 2 or x = 3
This formula works for any quadratic equation. The discriminant Δ = b² - 4ac determines the nature of the roots:
Transform the equation into the form (x + p)² = q, then take the square root of both sides.
x² + 6x = -2
x² + 6x + 9 = -2 + 9 (add (6/2)² = 9 to both sides)
(x + 3)² = 7
x + 3 = ±√7
x = -3 ± √7
The vertex of the parabola is at the point (h, k). If a > 0, the parabola opens upward; if a < 0, it opens downward.
A function is a rule that assigns to each input exactly one output. We write f(x) to denote the output of function f when the input is x.
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If f(x) = 2x + 3, then:
First apply g to x, then apply f to the result.
If f(x) = x² and g(x) = x + 1, then:
(f ∘ g)(x) = f(g(x)) = f(x + 1) = (x + 1)² = x² + 2x + 1
(g ∘ f)(x) = g(f(x)) = g(x²) = x² + 1
Notice that f ∘ g ≠ g ∘ f in general!
A system of equations is a set of two or more equations with the same variables. The solution is the set of values that satisfies all equations simultaneously.
Solve one equation for one variable, then substitute into the other equation.
Solve: y = 2x + 1 and 3x + y = 11
Substitute y = 2x + 1 into the second equation:
3x + (2x + 1) = 11
5x + 1 = 11
5x = 10, so x = 2
Then y = 2(2) + 1 = 5
Solution: (2, 5)
Add or subtract equations to eliminate one variable.
Graph both equations and find the intersection point(s).
Exponents represent repeated multiplication. Understanding the laws of exponents is crucial for simplifying expressions.
A radical is the inverse operation of an exponent. The most common is the square root:
√72 = √(36 × 2) = √36 × √2 = 6√2
Factoring is the process of writing an expression as a product of simpler expressions. It's essential for solving equations and simplifying rational expressions.
Factor out the largest factor common to all terms:
Group: (x³ + 3x²) + (2x + 6)
Factor each group: x²(x + 3) + 2(x + 3)
Factor out (x + 3): (x + 3)(x² + 2)
A rational expression is a fraction whose numerator and denominator are both polynomials. Understanding rational expressions is essential for advanced algebra and calculus.
Factor the numerator and denominator, then cancel common factors:
Step 1: Factor the numerator: x² − 9 = (x + 3)(x − 3)
Step 2: Factor the denominator: x² + 5x + 6 = (x + 2)(x + 3)
Step 3: Cancel the common factor (x + 3):
= (x − 3)/(x + 2), where x ≠ −3
Factor first, cancel common factors, then multiply what remains.
Multiply by the reciprocal of the divisor.
To add or subtract rational expressions, find a common denominator:
LCD = (x + 1)(x − 1)
= 3(x − 1)/[(x + 1)(x − 1)] + 2(x + 1)/[(x + 1)(x − 1)]
= [3(x − 1) + 2(x + 1)] / [(x + 1)(x − 1)]
= [3x − 3 + 2x + 2] / (x² − 1)
= (5x − 1)/(x² − 1)
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 solve an equation containing rational expressions, multiply both sides by the LCD to eliminate fractions, then solve the resulting polynomial equation. Always check for extraneous solutions — values that make the original denominators zero.
Step 1: Multiply both sides by (x − 2):
x + 3(x − 2) = 2
Step 2: Expand and solve: x + 3x − 6 = 2 → 4x = 8 → x = 2
Step 3: Check: x = 2 makes the denominator zero. No solution!
A logarithm answers the question: "What exponent do I need?" If bˣ = y, then log_b(y) = x. Logarithms are the inverse of exponential functions.
= log₂(8x³) − log₂(y) (quotient rule)
= log₂(8) + log₂(x³) − log₂(y) (product rule)
= 3 + 3·log₂(x) − log₂(y) (since 2³ = 8 and power rule)
Convert to exponential form: 3⁴ = 2x + 1
81 = 2x + 1
2x = 80
x = 40
Step 1: Combine left side: ln(x(x − 2)) = ln(3)
Step 2: Since ln is one-to-one: x(x − 2) = 3
Step 3: Solve: x² − 2x − 3 = 0 → (x − 3)(x + 1) = 0 → x = 3 or x = −1
Step 4: Check domain: ln(x) requires x > 0, and ln(x − 2) requires x > 2.
So x = −1 is extraneous. Solution: x = 3
When the variable is in the exponent, use logarithms to bring it down:
Take ln of both sides: x · ln(5) = ln(200)
x = ln(200)/ln(5) ≈ 5.298/1.609 ≈ 3.292
Take ln of both sides: (2x + 1)ln(3) = (x − 1)ln(7)
2x·ln(3) + ln(3) = x·ln(7) − ln(7)
2x·ln(3) − x·ln(7) = −ln(7) − ln(3)
x(2·ln(3) − ln(7)) = −(ln(7) + ln(3))
x = −(ln(7) + ln(3)) / (2·ln(3) − ln(7))
x = −ln(21) / (ln(9) − ln(7)) = −ln(21) / ln(9/7) ≈ −12.15
When we encounter equations like x² + 1 = 0, there is no real number solution because no real number squared gives −1. To solve such equations, mathematicians introduced the imaginary unit:
A complex number has the form a + bi, where a is the real part and b is the imaginary part.
Use FOIL and remember that i² = −1.
= 3(1) + 3(−4i) + 2i(1) + 2i(−4i)
= 3 − 12i + 2i − 8i²
= 3 − 10i − 8(−1)
= 3 − 10i + 8 = 11 − 10i
The conjugate of z = a + bi is z̄ = a − bi. Key property:
Multiply numerator and denominator by the conjugate of the denominator:
= (2 + 3i)(1 + i) / ((1 − i)(1 + i))
= (2 + 2i + 3i + 3i²) / (1 + 1)
= (2 + 5i − 3) / 2
= (−1 + 5i)/2 = −1/2 + 5i/2
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 numbers can be plotted on the complex plane (Argand diagram), where the horizontal axis represents the real part and the vertical axis represents the imaginary part.
This is the distance from the origin to the point (a, b).
Where r = |z| is the modulus and θ = arg(z) is the argument (angle).
The powers of i cycle with period 4:
To find iⁿ, divide n by 4 and use the remainder: iⁿ = i^(n mod 4).
A sequence is an ordered list of numbers following a pattern. A series is the sum of the terms of a sequence.
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 term differs from the previous by a constant common difference d:
This is an arithmetic series with a₁ = 1, aₙ = 100, n = 100
S₁₀₀ = 100/2 · (1 + 100) = 50 · 101 = 5050
(This is the famous result young Gauss discovered!)
Each term is multiplied by a constant common ratio r:
This is infinite geometric series with a₁ = 3, r = 1/2
TmpkUSsLzts5thZnn/yCakr7uSaPkTkoZ0NhLKDHnICyAfYnJsviZP4NfDjjoOMZrOFjWgwb0g5L23kCQLtp0PILlBfU9UWv5Kzvqf44hqUDyFjqAuvapNbiR9j7jdCKnfoGF0pCgnehmT6Em1MT6ZIfZ9Jb/2XbVQsUztgF0xXUIFsFS5j5wp9EKBh9Kuz50a/OJlTU4Vls1jiFhPhXSaAXM4E/CAV/ffocNvNgU4ChagEFRfpKv2k877iylunlIP4HzaYCLoSoyDWdhKXb/9zOg2tEHkQvSAKBuB6tUZ0uBC0h/Ij9dSJaZo+TkqybbP6a50Oz3bkELxNtYxCQvN6tVlY1wSwpKYoccf9JXcBJIc3BPt1afi7///Yk6K+MLAksVhz/xiltMPbSwE3ZVT3QsSh1jU+z7WGiGGLeq/Mg1gYf/4A+cvRoMZ2bfF5cMt0CTgT042l3GLG/j6rwNYuD1jUqAEgAquYFmKQdyWXfAj+7kT12JQ/0hKHEo0g8Emq9dj9TCj8GtRWfRSmBy8xxKbrDaXii0+IcHixDgVt2DDu87dc1B2rz069bAuxGAPA6nt4TMWeM6y3F5iUJ/yImFw1aVK42keAwDGDCytRPqdgbi+IsrZo7L5QunYATfKcnXQsyiVyeHKRG9QC2TjHe44J7XgJCNffjNOXExUjekI0W+kzNFYfJdVaLKn07RD9PkN0RF2aY4nd9r5z50K15qfWovUiZFfOezq3w+EhkY03VUDkTMGjj7UVcRxIywRuiqh913nc+M7ltxrt7C6oTBwd0H7y4pEGoSS5ZvmCKtD1iNiaznRlUZkzKoCeAPetnovYFCC8sse8wf+5imUCeysQyt34bxqRM6giggm1ICpX7+o+tDenUfmKZ07A0xBdakE/A5swSlxYYfjDSJ3USince |r| = 1/2 < 1, the series converges:
S∞ = 3/(1 − 1/2) = 3/(1/2) = 6
Useful summation formulas:
The absolute value of a number is its distance from zero on the number line. It is always non-negative:
For |expression| = k where k > 0:
Case 1: 2x − 5 = 7 → 2x = 12 → x = 6
Case 2: 2x − 5 = −7 → 2x = −2 → x = −1
Solutions: x = 6 or x = −1
−8 ≤ 3x + 1 ≤ 8
−9 ≤ 3x ≤ 7
−3 ≤ x ≤ 7/3
Matrices provide a powerful way to solve systems of equations and appear throughout higher mathematics. Here's a preview.
The system:
Can be written in matrix form as:
For the system ax + by = e and cx + dy = f:
This works when ad − bc ≠ 0 (the determinant is nonzero).
2x + 3y = 7 and x − y = 1
D = (2)(−1) − (3)(1) = −2 − 3 = −5
x = [(7)(−1) − (3)(1)] / (−5) = [−7 − 3] / (−5) = −10/(−5) = 2
y = [(2)(1) − (7)(1)] / (−5) = [2 − 7] / (−5) = −5/(−5) = 1
Solution: (2, 1). Check: 2(2) + 3(1) = 7 ✓, 2 − 1 = 1 ✓
Translating real-world situations into algebraic equations is one of the most practical skills in mathematics.
Maria is 4 years older than twice Tom's age. In 5 years, the sum of their ages will be 50. How old are they now?
Let Tom's current age = t. Then Maria's age = 2t + 4.
In 5 years: (t + 5) + (2t + 4 + 5) = 50
3t + 14 = 50 → 3t = 36 → t = 12
Tom is 12, Maria is 28.
Check: In 5 years: 17 + 33 = 50 ✓
A chemist has a 30% acid solution and a 70% acid solution. How many liters of each must be mixed to obtain 10 liters of a 40% acid solution?
Let x = liters of 30% solution, then (10 − x) = liters of 70% solution.
Set up equation: 0.30x + 0.70(10 − x) = 0.40(10)
0.30x + 7 − 0.70x = 4
−0.40x = −3
x = 7.5 liters of 30% solution, 2.5 liters of 70% solution.
Check: 0.30(7.5) + 0.70(2.5) = 2.25 + 1.75 = 4.0 = 0.40(10) ✓
A train leaves Station A heading east at 60 mph. Two hours later, another train leaves Station A heading east at 90 mph. How long does it take the second train to catch up?
Key formula: distance = rate × time
Let t = time (hours) after the second train departs.
First train's distance: 60(t + 2) (it had a 2-hour head start)
Second train's distance: 90t
They meet when distances are equal: 60(t + 2) = 90t
60t + 120 = 90t → 120 = 30t → t = 4 hours
Dive deeper into specific algebra topics with our focused lessons: